Defined in header <stdlib.h> | ||
---|---|---|
void* malloc( size_t size ); |
Allocates size
bytes of uninitialized storage.
If allocation succeeds, returns a pointer that is suitably aligned for any object type with fundamental alignment.
If size
is zero, the behavior of malloc
is implementation-defined. For example, a null pointer may be returned. Alternatively, a non-null pointer may be returned; but such a pointer should not be dereferenced, and should be passed to free
to avoid memory leaks.
A previous call to | (since C11) |
size | - | number of bytes to allocate |
On success, returns the pointer to the beginning of newly allocated memory. To avoid a memory leak, the returned pointer must be deallocated with free()
or realloc()
.
On failure, returns a null pointer.
#include <stdio.h> #include <stdlib.h> int main(void) { int *p1 = malloc(4*sizeof(int)); // allocates enough for an array of 4 int int *p2 = malloc(sizeof(int[4])); // same, naming the type directly int *p3 = malloc(4*sizeof *p3); // same, without repeating the type name if(p1) { for(int n=0; n<4; ++n) // populate the array p1[n] = n*n; for(int n=0; n<4; ++n) // print it back out printf("p1[%d] == %d\n", n, p1[n]); } free(p1); free(p2); free(p3); }
Output:
p1[0] == 0 p1[1] == 1 p1[2] == 4 p1[3] == 9
deallocates previously allocated memory (function) |
|
C++ documentation for malloc |
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