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std::chrono::weekday_last::weekday_last

constexpr explicit weekday_last( const std::chrono::weekday& wd ) noexcept;
(since C++20)

Constructs a weekday_last object storing the weekday wd.

Notes

A more convenient way to construct a weekday_last is with weekday's operator[], i.e., wd[std::chrono::last].

Example

#include <chrono>
#include <iostream>
using namespace std::chrono;
 
int main() {
    const year_month_day ymd { floor<days>(system_clock::now()) };
    const weekday_last wdl { Sunday[last] }; // A last Sunday of a month
    const year_month_day last_sun { ymd.year() / ymd.month() / wdl };
 
    std::cout << "The last Sunday of current month falls on "
              << (int)last_sun.year() << '/'
              << (unsigned)last_sun.month() << '/'
              << (unsigned)last_sun.day() << '\n';
}

Possible output:

The last Sunday of current month falls on 2021/9/26

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