constexpr std::chrono::year_month_day_last&
operator+=( const std::chrono::years& dy ) const noexcept;
| (1) | (since C++20) |
constexpr std::chrono::year_month_day_last&
operator+=( const std::chrono::months& dm ) const noexcept;
| (2) | (since C++20) |
constexpr std::chrono::year_month_day_last&
operator-=( const std::chrono::years& dy ) const noexcept;
| (3) | (since C++20) |
constexpr std::chrono::year_month_day_last&
operator-=( const std::chrono::months& dm ) const noexcept;
| (4) | (since C++20) |
Modifies the time point *this represents by the duration dy or dm.
*this = *this + dy;
*this = *this + dm;
*this = *this - dy;
*this = *this - dm;
For durations that are convertible to both std::chrono::years and std::chrono::months, the years overloads (1,3) are preferred if the call would otherwise be ambiguous.
#include <iostream>
#include <chrono>
int main()
{
std::cout << std::boolalpha;
auto ymdl {11/std::chrono::last/2020};
ymdl += std::chrono::years(15);
std::cout << (ymdl.day() == std::chrono::day(30)) << ' '
<< (ymdl.month() == std::chrono::November) << ' '
<< (ymdl.year() == std::chrono::year(2035)) << ' ';
ymdl -= std::chrono::months(6);
std::cout << (ymdl.day() == std::chrono::day(31)) << ' '
<< (ymdl.month() == std::chrono::May) << ' '
<< (ymdl.year() == std::chrono::year(2035)) << '\n';
}Output:
true true true true true true
|
(C++20) | adds or subtracts a year_month_day_last and some number of years or months (function) |
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