constexpr std::chrono::year year() const noexcept; | (1) | (since C++20) |
constexpr std::chrono::month month() const noexcept; | (2) | (since C++20) |
constexpr std::chrono::weekday weekday() const noexcept; | (3) | (since C++20) |
constexpr std::chrono::weekday_last weekday_last() const noexcept; | (4) | (since C++20) |
Retrieves the field values stored in this year_month_weekday_last object.
std::chrono::year value.std::chrono::month value.std::chrono::weekday value.std::chrono::weekday_last(weekday()).#include <iostream>
#include <chrono>
using namespace std::chrono;
int main()
{
std::cout << std::boolalpha;
auto ymwdl {Tuesday[last]/November/2022};
auto wdl = ymwdl.weekday_last();
wdl = (wdl.weekday() + days(1))[last];
ymwdl = {ymwdl.year() + years(1), ymwdl.month() - months(2), wdl};
std::cout << (year_month_day(ymwdl) == September/27/2023) << '\n';
}Output:
true
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