constexpr std::chrono::year year() const noexcept; | (1) | (since C++20) |
constexpr std::chrono::month month() const noexcept; | (2) | (since C++20) |
constexpr std::chrono::weekday weekday() const noexcept; | (3) | (since C++20) |
constexpr std::chrono::weekday_last weekday_last() const noexcept; | (4) | (since C++20) |
Retrieves the field values stored in this year_month_weekday_last
object.
std::chrono::year
value.std::chrono::month
value.std::chrono::weekday
value.std::chrono::weekday_last(weekday())
.#include <iostream> #include <chrono> using namespace std::chrono; int main() { std::cout << std::boolalpha; auto ymwdl {Tuesday[last]/November/2022}; auto wdl = ymwdl.weekday_last(); wdl = (wdl.weekday() + days(1))[last]; ymwdl = {ymwdl.year() + years(1), ymwdl.month() - months(2), wdl}; std::cout << (year_month_day(ymwdl) == September/27/2023) << '\n'; }
Output:
true
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