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std::filesystem::path::root_directory

path root_directory() const;
 (since C++17)

Returns the root directory of the generic-format path. If the path (in generic format) does not include root directory, returns path().

Parameters

(none).

Return value

The root directory of the path.

Exceptions

May throw implementation-defined exceptions.

Example

#include <iostream>
#include <filesystem>
namespace fs = std::filesystem;
 
int main()
{
    fs::path p = fs::current_path();
 
    std::cout << "The current path " << p << " decomposes into:\n"
              << "root name " << p.root_name() << '\n'
              << "root directory " << p.root_directory() << '\n'
              << "relative path " << p.relative_path() << '\n';
}

Possible output:

The current path "C:\Users\abcdef\Local Settings\temp" decomposes into:
root name "C:"
root directory "\"
relative path "Users\abcdef\Local Settings\temp"

See also

returns the root-name of the path, if present
(public member function)
returns the root path of the path, if present
(public member function)

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