(1) | ||
std::basic_string<CharT, Traits, Allocator> str() const; | (until C++20) | |
std::basic_string<CharT, Traits, Allocator> str() const&; | (since C++20) | |
template<class SAlloc> std::basic_string<CharT, Traits, SAlloc> str( const SAlloc& a ) const; | (2) | (since C++20) |
std::basic_string<CharT, Traits, Allocator> str() &&; | (3) | (since C++20) |
void str( const std::basic_string<CharT, Traits, Allocator>& s ); | (4) | |
template<class SAlloc> void str( const std::basic_string<CharT, Traits, SAlloc>& s ); | (5) | (since C++20) |
void str( std::basic_string<CharT, Traits, Allocator>&& s ); | (6) | (since C++20) |
Gets and sets the underlying string.
For the purpose of explanation, let mode
denote the open mode of the stream and buf_
denote the internal std::basic_string
object holding the underlying character sequence. Define buffer pointer initialization as follows:
bool(mode & std::ios_base::in) == true
), makes eback()
point at the first character, gptr() == eback()
, and egptr() == eback() + buf_.size()
: the subsequent input will read the first character of the string. bool(mode & std::ios_base::out) == true
), makes pbase()
points at the first character and epptr() >= pbase() + buf_.size()
(epptr()
is allowed to point farther so that the following sputc()
would not immediately call overflow()
).
| (since C++11) |
pptr() == pbase()
, so that subsequent output will overwrite the characters of the string. std::basic_string
object containing a copy of this std::basic_stringbuf
's underlying character sequence. For input-only streams, the returned string contains the characters from the range [
eback()
,
egptr()
)
. For input/output or output-only streams, contains the characters from pbase()
to the last character in the sequence regardless of egptr()
and epptr()
.str()
, or from a write operation. A typical implementation that uses over-allocation maintains a high-watermark pointer to track the end of the initialized part of the buffer and this overload returns the characters from pbase()
to the high-watermark pointer. Equivalent to return std::basic_string<CharT, Traits, Allocator>(view(), get_allocator()); . | (since C++20) |
a
is used to construct the returned std::basic_string
. Equivalent to return std::basic_string<CharT, Traits, SAlloc>(view(), a);
. This overload participates in overload resolution only if SAlloc
meets the requirements of Allocator.std::basic_string
object as if initialized with std::move(buf_)
. buf_
may need to be adjusted to contain the same content as in (1) at first. After construction of the std::basic_string
object, sets buf_
to empty and performs buffer pointer initialization, then returns the std::basic_string
object.buf_ = s
, then performs buffer pointer initialization.s
's allocator is not Allocator
. This overload participates in overload resolution only if SAlloc
and Allocator
are not the same type.buf_ = std::move(s)
, then performs buffer pointer initialization.s | - | a std::basic_string object holding the replacement character sequence |
a | - | allocator to use for all memory allocations of the returned std::basic_string |
std::basic_string
object holding this buffer's underlying character sequence.This function is typically accessed through std::basic_istringstream::str()
, std::basic_ostringstream::str()
, or std::basic_stringstream::str()
.
#include <iostream> #include <sstream> int main() { int n; std::istringstream in; // could also use in("1 2") in.rdbuf()->str("1 2"); // set the get area in >> n; std::cout << "after reading the first int from \"1 2\", the int is " << n << ", str() = \"" << in.rdbuf()->str() << "\"\n"; // or in.str() std::ostringstream out("1 2"); out << 3; std::cout << "after writing the int '3' to output stream \"1 2\"" << ", str() = \"" << out.str() << "\"\n"; std::ostringstream ate("1 2", std::ios_base::ate); // C++11 ate << 3; std::cout << "after writing the int '3' to append stream \"1 2\"" << ", str() = \"" << ate.str() << "\"\n"; }
Output:
after reading the first int from "1 2", the int is 1, str() = "1 2" after writing the int '3' to output stream "1 2", str() = "3 2" after writing the int '3' to append stream "1 2", str() = "1 23"
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 432 | C++98 | 1. overload (1) did not specify the content of the underlying character sequence 2. overload (4) did not specify how the input and output sequences are initialized | both specified |
LWG 562 | C++98 | overload (4) set epptr() to point one past the last underlyingcharacter if bool(mode & std::ios_base::out) == true | epptr() can be setbeyond that position |
gets or sets the contents of underlying string device object (public member function of std::basic_stringstream<CharT,Traits,Allocator> ) |
|
(C++20) | obtains a view over the underlying character sequence (public member function) |
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