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std::move_iterator<Iter>::operator*,->

	(1)
reference operator* () const;		(since C++11) (until C++17)
constexpr reference operator* () const;		(since C++17)
	(2)
pointer operator->() const;		(since C++11) (until C++17)
constexpr pointer operator->() const;		(since C++17) (deprecated in C++20)

Returns an rvalue-reference or pointer to the current element.

1) Equivalent to static_cast<reference>(*base()) (until C++20)ranges::iter_move(base()) (since C++20).

2) Equivalent to base().

Parameters

(none).

Return value

1) Rvalue-reference to the current element or its copy.

2) Copy of the underlying iterator. A pointer to the current element is eventually returned if -> is directly used.

Notes

Note that (2) eventually returns a pointer if -> is directly used. When dereferencing a pointer the returned value is an lvalue. This may lead to unintended behavior.

Example

#include <iomanip>
#include <iostream>
#include <iterator>
#include <string>
#include <vector>
 
void print(auto rem, auto const& v)
{
    for (std::cout << rem; auto const& e : v)
        std::cout << quoted(e) << ' ';
    std::cout << '\n';
}
 
int main()
{
    std::vector<std::string> p{"alpha", "beta", "gamma", "delta"}, q;
    print("1) p: ", p);
    for (std::move_iterator it{p.begin()}, end{p.end()}; it != end; ++it)
    {
        it->push_back('!'); // calls -> string::push_back(char)
        q.emplace_back( *it );
    }
    print("2) p: ", p);
    print("3) q: ", q);
 
    std::vector v{1,2,3};
    std::move_iterator it{v.begin()};
    // *it = 13; // error: using rvalue as lvalue
}

Output:

1) p: "alpha" "beta" "gamma" "delta"
2) p: "" "" "" ""
3) q: "alpha!" "beta!" "gamma!" "delta!"

Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.