void deallocate( T* p, std::size_t n );

Deallocates the storage referenced by the pointer p, which must be a pointer obtained by an earlier call to allocate().

The argument n must be equal to the first argument of the call to allocate() that originally produced p; otherwise, the behavior is undefined.

Calls ::operator delete(void*) or ::operator delete(void*, std::align_val_t) (since C++17), but it is unspecified when and how it is called.


p - pointer obtained from allocate()
n - number of objects earlier passed to allocate()

Return value


See also

allocates uninitialized storage
(public member function)
deallocates storage using the allocator
(public static member function of std::allocator_traits<Alloc>)

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