std::log10, std::log10f, std::log10l

float       log10 ( float num );
double      log10 ( double num );
long double log10 ( long double num );

/* floating-point-type */
            log10 ( /* floating-point-type */ num );

float       log10f( float num );

long double log10l( long double num );

template< class Integer >
double      log10 ( Integer num );

double

Parameters

Return value

If no errors occur, the common (base-10) logarithm of num (log
10(num) or lg(num)) is returned.

If a domain error occurs, an implementation-defined value is returned (NaN where supported).

If a pole error occurs, -HUGE_VAL, -HUGE_VALF, or -HUGE_VALL is returned.

Error handling

Errors are reported as specified in math_errhandling.

Domain error occurs if num is less than zero.

Pole error may occur if num is zero.

If the implementation supports IEEE floating-point arithmetic (IEC 60559),

• If the argument is ±0, -∞ is returned and FE_DIVBYZERO is raised.
• If the argument is 1, +0 is returned
• If the argument is negative, NaN is returned and FE_INVALID is raised.
• If the argument is +∞, +∞ is returned
• If the argument is NaN, NaN is returned

Notes

The additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that for their argument num of integer type, std::log10(num) has the same effect as std::log10(static_cast<double>(num)).

Example

#include <cerrno>
#include <cfenv>
#include <cmath>
#include <cstring>
#include <iostream>
 
// #pragma STDC FENV_ACCESS ON
 
int main()
{
    std::cout << "log10(1000) = " << std::log10(1000) << '\n'
              << "log10(0.001) = " << std::log10(0.001) << '\n'
              << "base-5 logarithm of 125 = "
              << std::log10(125) / std::log10(5) << '\n';
 
    // special values
    std::cout << "log10(1) = " << std::log10(1) << '\n'
              << "log10(+Inf) = " << std::log10(INFINITY) << '\n';
 
    // error handling
    errno = 0;
    std::feclearexcept(FE_ALL_EXCEPT);
 
    std::cout << "log10(0) = " << std::log10(0) << '\n';
 
    if (errno == ERANGE)
        std::cout << "    errno == ERANGE: " << std::strerror(errno) << '\n';
    if (std::fetestexcept(FE_DIVBYZERO))
        std::cout << "    FE_DIVBYZERO raised\n";
}

log10(1000) = 3
log10(0.001) = -3
base-5 logarithm of 125 = 3
log10(1) = 0
log10(+Inf) = inf
log10(0) = -inf
    errno == ERANGE: Numerical result out of range
    FE_DIVBYZERO raised

See also