constexpr auto size() requires ranges::sized_range<V>; | (since C++23) | |
constexpr auto size() const requires ranges::sized_range<const V>; | (since C++23) |
Returns the number of elements.
Let base_
and n_
be the underlying view and "window size" respectively.
Equivalent to:
auto sz = ranges::distance(base_) - n_ + 1; if (sz < 0) sz = 0; return __to_unsigned_like(sz);
(none).
The number of elements. Equals to 0
, if the number of elements (ranges::size(base_)
) in underlying view base_
is less than "window size" n_
.
A link to test: Compiler Explorer.
#include <forward_list> #include <iostream> #include <list> #include <ranges> int main() { constexpr static auto v = {1, 2, 3, 4, 5, 6}; constexpr int width1{4}; constexpr auto view1{std::views::slide(v, width1)}; static_assert(view1.size() == 3); static_assert(view1.size() == (v.size() - width1 + 1)); constexpr int width2{8}; constexpr auto view2{std::views::slide(v, width2)}; // window is too wide, so view2 has no elements: static_assert(view2.size() == 0); std::forward_list forward_list = v; const auto view3{std::views::slide(forward_list, width1)}; // auto x = view3.size(); // error: sized_range constraint is not satisfied std::list list = v; const auto view4{std::views::slide(list, width1)}; std::cout << view4.size() << '\n'; // prints 3 }
Output:
3
(C++20) | returns an integer equal to the size of a range (customization point object) |
(C++20) | returns a signed integer equal to the size of a range (customization point object) |
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