constexpr const ranges::iterator_t<Base>& base() const & noexcept; | (1) | (since C++20) |
constexpr ranges::iterator_t<Base> base() &&; | (2) | (since C++20) |
Returns the underlying iterator.
(none).
#include <algorithm> #include <iostream> #include <iterator> #include <ranges> int main() { const auto v = { 0, 1, 2, 3, 4 }; auto x2 = [](int x) { return x << 1; }; std::ranges::transform_view tv{ v, x2 }; std::ostream_iterator<int> ostr{ std::cout, " " }; std::ranges::copy(v, ostr), std::cout << '\n'; std::ranges::copy(tv.base(), ostr), std::cout << '\n'; std::ranges::copy(tv, ostr), std::cout << '\n'; }
Output:
0 1 2 3 4 0 1 2 3 4 0 2 4 6 8
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 3533 | C++20 | the const& overload of base returns a copy of the underlying iterator | returns a reference |
LWG 3593 | C++20 | the const& overload of base might not be noexcept | made noexcept |
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