Defined in header <cstddef> | ||
|---|---|---|
enum class byte : unsigned char {};
| (since C++17) |
std::byte is a distinct type that implements the concept of byte as specified in the C++ language definition.
Like char and unsigned char, it can be used to access raw memory occupied by other objects (object representation), but unlike those types, it is not a character type and is not an arithmetic type. A byte is only a collection of bits, and only bitwise operators are defined for it.
template <class IntegerType> constexpr IntegerType to_integer( std::byte b ) noexcept; | (since C++17) |
Equivalent to: return IntegerType(b); This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.
template <class IntegerType> constexpr std::byte& operator<<=( std::byte& b, IntegerType shift ) noexcept; | (1) | (since C++17) |
template <class IntegerType> constexpr std::byte& operator>>=( std::byte& b, IntegerType shift ) noexcept; | (2) | (since C++17) |
return b = b << shift; This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.return b = b >> shift; This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.
template <class IntegerType> constexpr std::byte operator<<( std::byte b, IntegerType shift ) noexcept; | (1) | (since C++17) |
template <class IntegerType> constexpr std::byte operator>>( std::byte b, IntegerType shift ) noexcept; | (2) | (since C++17) |
return std::byte(static_cast<unsigned int>(b) << shift); This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.return std::byte(static_cast<unsigned int>(b) >> shift); This overload participates in overload resolution only if std::is_integral_v<IntegerType> is true.
constexpr std::byte& operator|=( std::byte& l, std::byte r ) noexcept; | (1) | (since C++17) |
constexpr std::byte& operator&=( std::byte& l, std::byte r ) noexcept; | (2) | (since C++17) |
constexpr std::byte& operator^=( std::byte& l, std::byte r ) noexcept; | (3) | (since C++17) |
return l = l | r;.return l = l & r;.return l = l ^ r;. constexpr std::byte operator|( std::byte l, std::byte r ) noexcept; | (1) | (since C++17) |
constexpr std::byte operator&( std::byte l, std::byte r ) noexcept; | (2) | (since C++17) |
constexpr std::byte operator^( std::byte l, std::byte r ) noexcept; | (3) | (since C++17) |
constexpr std::byte operator~( std::byte b ) noexcept; | (4) | (since C++17) |
return std::byte(static_cast<unsigned int>(l) | static_cast<unsigned int>(r));.return std::byte(static_cast<unsigned int>(l) & static_cast<unsigned int>(r));.return std::byte(static_cast<unsigned int>(l) ^ static_cast<unsigned int>(r));.return std::byte(~static_cast<unsigned int>(b)); A numeric value n can be converted to a byte value using std::byte{n}, due to C++17 relaxed enum class initialization rules.
A byte can be converted to a numeric value (such as to produce an integer hash of an object) the usual way with an explicit conversion or alternatively with std::to_integer.
| Feature-test macro | Value | Std | Comment |
|---|---|---|---|
__cpp_lib_byte | 201603L | (C++17) |
std::byte |
#include <bitset>
#include <cstddef>
#include <iostream>
std::ostream& operator<<(std::ostream& os, std::byte b)
{
return os << std::bitset<8>(std::to_integer<int>(b));
}
int main()
{
std::byte b{42};
std::cout << "1. " << b << '\n';
// b *= 2 compilation error
b <<= 1;
std::cout << "2. " << b << '\n';
b >>= 1;
std::cout << "3. " << b << '\n';
std::cout << "4. " << (b << 1) << '\n';
std::cout << "5. " << (b >> 1) << '\n';
b |= std::byte{0b11110000};
std::cout << "6. " << b << '\n';
b &= std::byte{0b11110000};
std::cout << "7. " << b << '\n';
b ^= std::byte{0b11111111};
std::cout << "8. " << b << '\n';
}Output:
1. 00101010 2. 01010100 3. 00101010 4. 01010100 5. 00010101 6. 11111010 7. 11110000 8. 00001111
© cppreference.com
Licensed under the Creative Commons Attribution-ShareAlike Unported License v3.0.
https://en.cppreference.com/w/cpp/types/byte