Defined in header <cstddef> | ||
---|---|---|
enum class byte : unsigned char {}; | (since C++17) |
std::byte
is a distinct type that implements the concept of byte as specified in the C++ language definition.
Like char
and unsigned char
, it can be used to access raw memory occupied by other objects (object representation), but unlike those types, it is not a character type and is not an arithmetic type. A byte is only a collection of bits, and only bitwise operators are defined for it.
template <class IntegerType> constexpr IntegerType to_integer( std::byte b ) noexcept; | (since C++17) |
Equivalent to: return IntegerType(b);
This overload participates in overload resolution only if std::is_integral_v<IntegerType>
is true.
template <class IntegerType> constexpr std::byte& operator<<=( std::byte& b, IntegerType shift ) noexcept; | (1) | (since C++17) |
template <class IntegerType> constexpr std::byte& operator>>=( std::byte& b, IntegerType shift ) noexcept; | (2) | (since C++17) |
return b = b << shift;
This overload participates in overload resolution only if std::is_integral_v<IntegerType>
is true.return b = b >> shift;
This overload participates in overload resolution only if std::is_integral_v<IntegerType>
is true.
template <class IntegerType> constexpr std::byte operator<<( std::byte b, IntegerType shift ) noexcept; | (1) | (since C++17) |
template <class IntegerType> constexpr std::byte operator>>( std::byte b, IntegerType shift ) noexcept; | (2) | (since C++17) |
return std::byte(static_cast<unsigned int>(b) << shift);
This overload participates in overload resolution only if std::is_integral_v<IntegerType>
is true.return std::byte(static_cast<unsigned int>(b) >> shift);
This overload participates in overload resolution only if std::is_integral_v<IntegerType>
is true.
constexpr std::byte& operator|=( std::byte& l, std::byte r ) noexcept; | (1) | (since C++17) |
constexpr std::byte& operator&=( std::byte& l, std::byte r ) noexcept; | (2) | (since C++17) |
constexpr std::byte& operator^=( std::byte& l, std::byte r ) noexcept; | (3) | (since C++17) |
return l = l | r;
.return l = l & r;
.return l = l ^ r;
. constexpr std::byte operator|( std::byte l, std::byte r ) noexcept; | (1) | (since C++17) |
constexpr std::byte operator&( std::byte l, std::byte r ) noexcept; | (2) | (since C++17) |
constexpr std::byte operator^( std::byte l, std::byte r ) noexcept; | (3) | (since C++17) |
constexpr std::byte operator~( std::byte b ) noexcept; | (4) | (since C++17) |
return std::byte(static_cast<unsigned int>(l) | static_cast<unsigned int>(r));
.return std::byte(static_cast<unsigned int>(l) & static_cast<unsigned int>(r));
.return std::byte(static_cast<unsigned int>(l) ^ static_cast<unsigned int>(r));
.return std::byte(~static_cast<unsigned int>(b));
A numeric value n
can be converted to a byte value using std::byte{n}
, due to C++17 relaxed enum class initialization rules.
A byte can be converted to a numeric value (such as to produce an integer hash of an object) the usual way with an explicit conversion or alternatively with std::to_integer
.
Feature-test macro | Value | Std | Comment |
---|---|---|---|
__cpp_lib_byte | 201603L | (C++17) |
std::byte |
#include <bitset> #include <cstddef> #include <iostream> std::ostream& operator<<(std::ostream& os, std::byte b) { return os << std::bitset<8>(std::to_integer<int>(b)); } int main() { std::byte b{42}; std::cout << "1. " << b << '\n'; // b *= 2 compilation error b <<= 1; std::cout << "2. " << b << '\n'; b >>= 1; std::cout << "3. " << b << '\n'; std::cout << "4. " << (b << 1) << '\n'; std::cout << "5. " << (b >> 1) << '\n'; b |= std::byte{0b11110000}; std::cout << "6. " << b << '\n'; b &= std::byte{0b11110000}; std::cout << "7. " << b << '\n'; b ^= std::byte{0b11111111}; std::cout << "8. " << b << '\n'; }
Output:
1. 00101010 2. 01010100 3. 00101010 4. 01010100 5. 00010101 6. 11111010 7. 11110000 8. 00001111
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