Defined in header <type_traits> | ||
---|---|---|
template< class T, unsigned N = 0 > struct extent; | (since C++11) |
If T
is an array type, provides the member constant value
equal to the number of elements along the N
th dimension of the array, if N
is in [
0
,
std::rank<T>::value
)
. For any other type, or if T
is an array of unknown bound along its first dimension and N
is 0, value
is 0.
The behavior of a program that adds specializations for extent
or extent_v
(since C++17) is undefined.
template< class T, unsigned N = 0 > inline constexpr std::size_t extent_v = extent<T, N>::value; | (since C++17) |
value
[static] | the number of elements along the N th dimension of T (public static member constant) |
operator std::size_t | converts the object to std::size_t, returns value (public member function) |
operator()
(C++14) | returns value (public member function) |
Type | Definition |
---|---|
value_type | std::size_t |
type | std::integral_constant<std::size_t, value> |
template<class T, unsigned N = 0> struct extent : std::integral_constant<std::size_t, 0> {}; template<class T> struct extent<T[], 0> : std::integral_constant<std::size_t, 0> {}; template<class T, unsigned N> struct extent<T[], N> : std::extent<T, N - 1> {}; template<class T, std::size_t I> struct extent<T[I], 0> : std::integral_constant<std::size_t, I> {}; template<class T, std::size_t I, unsigned N> struct extent<T[I], N> : std::extent<T, N - 1> {}; |
#include <iostream> #include <type_traits> int main() { std::cout << std::extent<int[3]>::value << '\n'; //< default dimension is 0 std::cout << std::extent<int[3][4], 0>::value << '\n'; std::cout << std::extent<int[3][4], 1>::value << '\n'; std::cout << std::extent<int[3][4], 2>::value << '\n'; std::cout << std::extent<int[]>::value << '\n'; const auto ext = std::extent<int[9]>{}; std::cout << ext << '\n'; //< implicit conversion to std::size_t const int ints[] = {1, 2, 3, 4}; std::cout << std::extent<decltype(ints)>::value << '\n'; //< array size [[maybe_unused]] int ary[][3] = { {1, 2, 3} }; // ary[0] is type of reference of 'int[3]', so, extent // cannot calculate correctly and return 0 static_assert(std::is_same_v<decltype(ary[0]), int(&)[3]>); std::cout << std::extent<decltype(ary[0])>::value << '\n'; // removing reference will give correct extent value 3 std::cout << std::extent<std::remove_cvref_t<decltype(ary[0])>>::value << '\n'; }
Output:
3 3 4 0 0 9 4 0 3
(C++11) | checks if a type is an array type (class template) |
(C++11) | obtains the number of dimensions of an array type (class template) |
(C++11) | removes one extent from the given array type (class template) |
(C++11) | removes all extents from the given array type (class template) |
© cppreference.com
Licensed under the Creative Commons Attribution-ShareAlike Unported License v3.0.
https://en.cppreference.com/w/cpp/types/extent