| Defined in header <type_traits> | ||
|---|---|---|
| template< class T > struct is_copy_assignable; | (1) | (since C++11) | 
| template< class T > struct is_trivially_copy_assignable; | (2) | (since C++11) | 
| template< class T > struct is_nothrow_copy_assignable; | (3) | (since C++11) | 
T is not a referenceable type (i.e., possibly cv-qualified void or a function type with a cv-qualifier-seq or a ref-qualifier), provides a member constant value equal to false. Otherwise, provides a member constant value equal to std::is_assignable<T&, const T&>::value.T shall be a complete type, (possibly cv-qualified) void, or an array of unknown bound. Otherwise, the behavior is undefined.
If an instantiation of a template above depends, directly or indirectly, on an incomplete type, and that instantiation could yield a different result if that type were hypothetically completed, the behavior is undefined.
The behavior of a program that adds specializations for any of the templates described on this page is undefined.
| template< class T > inline constexpr bool is_copy_assignable_v = is_copy_assignable<T>::value; | (since C++17) | |
| template< class T > inline constexpr bool is_trivially_copy_assignable_v = is_trivially_copy_assignable<T>::value; | (since C++17) | |
| template< class T > inline constexpr bool is_nothrow_copy_assignable_v = is_nothrow_copy_assignable<T>::value; | (since C++17) | 
| value [static] | trueifTis copy-assignable,falseotherwise(public static member constant) | 
| operator bool | converts the object to bool, returns value(public member function) | 
| operator() (C++14) | returns value(public member function) | 
| Type | Definition | 
|---|---|
| value_type | bool | 
| type | std::integral_constant<bool, value> | 
| template<class T>
struct is_copy_assignable
    : std::is_assignable<typename std::add_lvalue_reference<T>::type,
                         typename std::add_lvalue_reference<const T>::type> {};
 
template<class T>
struct is_trivially_copy_assignable
    : std::is_trivially_assignable<typename std::add_lvalue_reference<T>::type,
                                   typename std::add_lvalue_reference<const T>::type> {};
 
template<class T>
struct is_nothrow_copy_assignable
    : std::is_nothrow_assignable<typename std::add_lvalue_reference<T>::type,
                                 typename std::add_lvalue_reference<const T>::type> {}; | 
The trait std::is_copy_assignable is less strict than CopyAssignable because it does not check the type of the result of the assignment (which, for a CopyAssignable type, must be an lvalue of type T) and does not check the semantic requirement that the argument expression remains unchanged. It also does not check that T satisfies MoveAssignable, which is required of all CopyAssignable types.
#include <iostream>
#include <type_traits>
#include <utility>
 
struct Foo { int n; };
 
int main()
{
    std::cout << std::boolalpha
              << "Foo is trivially copy-assignable? "
              << std::is_trivially_copy_assignable<Foo>::value << '\n'
              << "int[2] is copy-assignable? "
              << std::is_copy_assignable<int[2]>::value << '\n'
              << "int is nothrow copy-assignable? "
              << std::is_nothrow_copy_assignable<int>::value << '\n';
}Output:
Foo is trivially copy-assignable? true int[2] is copy-assignable? false int is nothrow copy-assignable? true
| (C++11)(C++11)(C++11) | checks if a type has an assignment operator for a specific argument (class template) | 
| (C++11)(C++11)(C++11) | checks if a type has a move assignment operator (class template) | 
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