constexpr const T* operator->() const noexcept; | (1) | (since C++17) |
constexpr T* operator->() noexcept; | (1) | (since C++17) |
constexpr const T& operator*() const& noexcept; | (2) | (since C++17) |
constexpr T& operator*() & noexcept; | (2) | (since C++17) |
constexpr const T&& operator*() const&& noexcept; | (2) | (since C++17) |
constexpr T&& operator*() && noexcept; | (2) | (since C++17) |
Accesses the contained value.
The behavior is undefined if *this
does not contain a value.
(none).
Pointer or reference to the contained value.
This operator does not check whether the optional contains a value! You can do so manually by using has_value()
or simply operator bool()
. Alternatively, if checked access is needed, value()
or value_or()
may be used.
#include <optional> #include <iostream> #include <string> int main() { using namespace std::string_literals; std::optional<int> opt1 = 1; std::cout<< "opt1: " << *opt1 << '\n'; *opt1 = 2; std::cout<< "opt1: " << *opt1 << '\n'; std::optional<std::string> opt2 = "abc"s; std::cout<< "opt2: " << *opt2 << " size: " << opt2->size() << '\n'; // You can "take" the contained value by calling operator* on a rvalue to optional auto taken = *std::move(opt2); std::cout << "taken: " << taken << " opt2: " << *opt2 << "size: " << opt2->size() << '\n'; }
Output:
opt1: 1 opt1: 2 opt2: abc size: 3 taken: abc opt2: size: 0
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 2762 | C++17 | operator-> and operator* might be potentially-throwing | made noexcept |
returns the contained value (public member function) |
|
returns the contained value if available, another value otherwise (public member function) |
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