Require or disallow logical assignment logical operator shorthand
Some problems reported by this rule are automatically fixable by the --fix
command line option
Some problems reported by this rule are manually fixable by editor suggestions
ES2021 introduces the assignment operator shorthand for the logical operators ||
, &&
and ??
. Before, this was only allowed for mathematical operations such as +
or *
(see the rule operator-assignment). The shorthand can be used if the assignment target and the left expression of a logical expression are the same. For example a = a || b
can be shortened to a ||= b
.
This rule requires or disallows logical assignment operator shorthand.
This rule has a string and an object option. String option:
"always"
(default)"never"
Object option (only available if string option is set to "always"
):
"enforceForIfStatements": false
(default) Do not check for equivalent if
statements"enforceForIfStatements": true
Check for equivalent if
statementsExamples of incorrect code for this rule with the default "always"
option:
/*eslint logical-assignment-operators: ["error", "always"]*/
a = a || b
a = a && b
a = a ?? b
a || (a = b)
a && (a = b)
a ?? (a = b)
Examples of correct code for this rule with the default "always"
option:
/*eslint logical-assignment-operators: ["error", "always"]*/
a = b
a += b
a ||= b
a = b || c
a || (b = c)
if (a) a = b
Examples of incorrect code for this rule with the "never"
option:
/*eslint logical-assignment-operators: ["error", "never"]*/
a ||= b
a &&= b
a ??= b
Examples of correct code for this rule with the "never"
option:
/*eslint logical-assignment-operators: ["error", "never"]*/
a = a || b
a = a && b
a = a ?? b
This option checks for additional patterns with if statements which could be expressed with the logical assignment operator.
Examples of incorrect code for this rule with the ["always", { enforceForIfStatements: true }]
option:
/*eslint logical-assignment-operators: ["error", "always", { enforceForIfStatements: true }]*/
if (a) a = b // <=> a &&= b
if (!a) a = b // <=> a ||= b
if (a == null) a = b // <=> a ??= b
if (a === null || a === undefined) a = b // <=> a ??= b
Examples of correct code for this rule with the ["always", { enforceForIfStatements: true }]
option:
/*eslint logical-assignment-operators: ["error", "always", { enforceForIfStatements: true }]*/
if (a) b = c
if (a === 0) a = b
Use of logical operator assignment shorthand is a stylistic choice. Leaving this rule turned off would allow developers to choose which style is more readable on a case-by-case basis.
This rule was introduced in ESLint v8.24.0.
© OpenJS Foundation and other contributors
Licensed under the MIT License.
https://eslint.org/docs/latest/rules/logical-assignment-operators