The delete()
method of Set
instances removes a specified value from this set, if it is in the set.
The delete()
method of Set
instances removes a specified value from this set, if it is in the set.
setInstance.delete(value)
value
The value to remove from Set
.
Returns true
if value
was already in Set
; otherwise false
.
const mySet = new Set(); mySet.add("foo"); console.log(mySet.delete("bar")); // false; no "bar" element found to be deleted. console.log(mySet.delete("foo")); // true; successfully removed. console.log(mySet.has("foo")); // false; the "foo" element is no longer present.
Because objects are compared by reference, you have to delete them by checking individual properties if you don't have a reference to the original object.
const setObj = new Set(); // Create a new set. setObj.add({ x: 10, y: 20 }); // Add object in the set. setObj.add({ x: 20, y: 30 }); // Add object in the set. // Delete any point with `x > 10`. setObj.forEach((point) => { if (point.x > 10) { setObj.delete(point); } });
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https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Set/delete