The &&=
operator only evaluates the right operand and assigns to the left if the left operand is truthy.
The &&=
operator only evaluates the right operand and assigns to the left if the left operand is truthy.
x &&= y
Logical AND assignment short-circuits, meaning that x &&= y
is equivalent to x && (x = y)
, except that the expression x
is only evaluated once.
No assignment is performed if the left-hand side is not truthy, due to short-circuiting of the logical AND operator. For example, the following does not throw an error, despite x
being const
:
const x = 0; x &&= 2;
Neither would the following trigger the setter:
const x = { get value() { return 0; }, set value(v) { console.log("Setter called"); }, }; x.value &&= 2;
In fact, if x
is not truthy, y
is not evaluated at all.
const x = 0; x &&= console.log("y evaluated"); // Logs nothing
let x = 0; let y = 1; x &&= 0; // 0 x &&= 1; // 0 y &&= 1; // 1 y &&= 0; // 0
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https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Logical_AND_assignment