Use the GROUP BY
clause in a SELECT statement to group rows together that have the same value in one or more column, or the same computed value using expressions with any functions and operators except grouping functions. When you use a GROUP BY
clause, you will get a single result row for each group of rows that have the same value for the expression given in GROUP BY
.
When grouping rows, grouping values are compared as if by the =
operator. For string values, the =
operator ignores trailing whitespace and may normalize characters and ignore case, depending on the collation in use.
You can use any of the grouping functions in your select expression. Their values will be calculated based on all the rows that have been grouped together for each result row. If you select a non-grouped column or a value computed from a non-grouped column, it is undefined which row the returned value is taken from. This is not permitted if the ONLY_FULL_GROUP_BY
SQL_MODE is used.
You can use multiple expressions in the GROUP BY
clause, separated by commas. Rows are grouped together if they match on each of the expressions.
You can also use a single integer as the grouping expression. If you use an integer n, the results will be grouped by the nth column in the select expression.
The WHERE
clause is applied before the GROUP BY
clause. It filters non-aggregated rows before the rows are grouped together. To filter grouped rows based on aggregate values, use the HAVING
clause. The HAVING
clause takes any expression and evaluates it as a boolean, just like the WHERE
clause. You can use grouping functions in the HAVING
clause. As with the select expression, if you reference non-grouped columns in the HAVING
clause, the behavior is undefined.
By default, if a GROUP BY
clause is present, the rows in the output will be sorted by the expressions used in the GROUP BY
. You can also specify ASC
or DESC
(ascending, descending) after those expressions, like in ORDER BY. The default is ASC
.
If you want the rows to be sorted by another field, you can add an explicit ORDER BY. If you don't want the result to be ordered, you can add ORDER BY NULL.
The WITH ROLLUP
modifer adds extra rows to the resultset that represent super-aggregate summaries. For a full description with examples, see SELECT WITH ROLLUP.
Consider the following table that records how many times each user has played and won a game:
CREATE TABLE plays (name VARCHAR(16), plays INT, wins INT); INSERT INTO plays VALUES ("John", 20, 5), ("Robert", 22, 8), ("Wanda", 32, 8), ("Susan", 17, 3);
Get a list of win counts along with a count:
SELECT wins, COUNT(*) FROM plays GROUP BY wins; +------+----------+ | wins | COUNT(*) | +------+----------+ | 3 | 1 | | 5 | 1 | | 8 | 2 | +------+----------+ 3 rows in set (0.00 sec)
The GROUP BY
expression can be a computed value, and can refer back to an identifer specified with AS
. Get a list of win averages along with a count:
SELECT (wins / plays) AS winavg, COUNT(*) FROM plays GROUP BY winavg; +--------+----------+ | winavg | COUNT(*) | +--------+----------+ | 0.1765 | 1 | | 0.2500 | 2 | | 0.3636 | 1 | +--------+----------+ 3 rows in set (0.00 sec)
You can use any grouping function in the select expression. For each win average as above, get a list of the average play count taken to get that average:
SELECT (wins / plays) AS winavg, AVG(plays) FROM plays GROUP BY winavg; +--------+------------+ | winavg | AVG(plays) | +--------+------------+ | 0.1765 | 17.0000 | | 0.2500 | 26.0000 | | 0.3636 | 22.0000 | +--------+------------+ 3 rows in set (0.00 sec)
You can filter on aggregate information using the HAVING
clause. The HAVING
clause is applied after GROUP BY
and allows you to filter on aggregate data that is not available to the WHERE
clause. Restrict the above example to results that involve an average number of plays over 20:
SELECT (wins / plays) AS winavg, AVG(plays) FROM plays GROUP BY winavg HAVING AVG(plays) > 20; +--------+------------+ | winavg | AVG(plays) | +--------+------------+ | 0.2500 | 26.0000 | | 0.3636 | 22.0000 | +--------+------------+ 2 rows in set (0.00 sec)
© 2019 MariaDB
Licensed under the Creative Commons Attribution 3.0 Unported License and the GNU Free Documentation License.
https://mariadb.com/kb/en/group-by/