numpy.expm1(x, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'expm1'>
Calculate exp(x)  1
for all elements in the array.
Parameters: 


Returns: 

See also
log1p
log(1 + x)
, the inverse of expm1.This function provides greater precision than exp(x)  1
for small values of x
.
The true value of exp(1e10)  1
is 1.00000000005e10
to about 32 significant digits. This example shows the superiority of expm1 in this case.
>>> np.expm1(1e10) 1.00000000005e10 >>> np.exp(1e10)  1 1.000000082740371e10
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https://docs.scipy.org/doc/numpy1.17.0/reference/generated/numpy.expm1.html