numpy.fft.ihfft(a, n=None, axis=-1, norm=None)
[source]
Compute the inverse FFT of a signal that has Hermitian symmetry.
Parameters: |
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Returns: |
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hfft
/ihfft
are a pair analogous to rfft
/irfft
, but for the opposite case: here the signal has Hermitian symmetry in the time domain and is real in the frequency domain. So here it’s hfft
for which you must supply the length of the result if it is to be odd:
ihfft(hfft(a, 2*len(a) - 2) == a
, within roundoff error,ihfft(hfft(a, 2*len(a) - 1) == a
, within roundoff error.>>> spectrum = np.array([ 15, -4, 0, -1, 0, -4]) >>> np.fft.ifft(spectrum) array([1.+0.j, 2.+0.j, 3.+0.j, 4.+0.j, 3.+0.j, 2.+0.j]) # may vary >>> np.fft.ihfft(spectrum) array([ 1.-0.j, 2.-0.j, 3.-0.j, 4.-0.j]) # may vary
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https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.fft.ihfft.html