numpy.gcd(x1, x2, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'gcd'>
Returns the greatest common divisor of x1
and x2
Parameters: 


Returns: 

See also
lcm
>>> np.gcd(12, 20) 4 >>> np.gcd.reduce([15, 25, 35]) 5 >>> np.gcd(np.arange(6), 20) array([20, 1, 2, 1, 4, 5])
© 2005–2019 NumPy Developers
Licensed under the 3clause BSD License.
https://docs.scipy.org/doc/numpy1.17.0/reference/generated/numpy.gcd.html