numpy.ma.getmask(a) [source]
Return the mask of a masked array, or nomask.
Return the mask of a as an ndarray if a is a MaskedArray and the mask is not nomask, else return nomask. To guarantee a full array of booleans of the same shape as a, use getmaskarray.
| Parameters: |
|
|---|
See also
getdata
getmaskarray
>>> import numpy.ma as ma
>>> a = ma.masked_equal([[1,2],[3,4]], 2)
>>> a
masked_array(
data=[[1, --],
[3, 4]],
mask=[[False, True],
[False, False]],
fill_value=2)
>>> ma.getmask(a)
array([[False, True],
[False, False]])
Equivalently use the MaskedArray mask attribute.
>>> a.mask
array([[False, True],
[False, False]])
Result when mask == nomask
>>> b = ma.masked_array([[1,2],[3,4]])
>>> b
masked_array(
data=[[1, 2],
[3, 4]],
mask=False,
fill_value=999999)
>>> ma.nomask
False
>>> ma.getmask(b) == ma.nomask
True
>>> b.mask == ma.nomask
True
© 2005–2019 NumPy Developers
Licensed under the 3-clause BSD License.
https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.ma.getmask.html