numpy.ma.where(condition, x=<no value>, y=<no value>)
[source]
Return a masked array with elements from x
or y
, depending on condition.
Note
When only condition
is provided, this function is identical to nonzero
. The rest of this documentation covers only the case where all three arguments are provided.
Parameters: |
|
---|---|
Returns: |
|
See also
numpy.where
nonzero
>>> x = np.ma.array(np.arange(9.).reshape(3, 3), mask=[[0, 1, 0], ... [1, 0, 1], ... [0, 1, 0]]) >>> x masked_array( data=[[0.0, --, 2.0], [--, 4.0, --], [6.0, --, 8.0]], mask=[[False, True, False], [ True, False, True], [False, True, False]], fill_value=1e+20) >>> np.ma.where(x > 5, x, -3.1416) masked_array( data=[[-3.1416, --, -3.1416], [--, -3.1416, --], [6.0, --, 8.0]], mask=[[False, True, False], [ True, False, True], [False, True, False]], fill_value=1e+20)
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https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.ma.where.html