numpy.nper(rate, pmt, pv, fv=0, when='end')
[source]
Compute the number of periodic payments.
decimal.Decimal
type is not supported.
Parameters: |
|
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The number of periods nper
is computed by solving the equation:
fv + pv*(1+rate)**nper + pmt*(1+rate*when)/rate*((1+rate)**nper-1) = 0
but if rate = 0
then:
fv + pv + pmt*nper = 0
If you only had $150/month to pay towards the loan, how long would it take to pay-off a loan of $8,000 at 7% annual interest?
>>> print(np.round(np.nper(0.07/12, -150, 8000), 5)) 64.07335
So, over 64 months would be required to pay off the loan.
The same analysis could be done with several different interest rates and/or payments and/or total amounts to produce an entire table.
>>> np.nper(*(np.ogrid[0.07/12: 0.08/12: 0.01/12, ... -150 : -99 : 50 , ... 8000 : 9001 : 1000])) array([[[ 64.07334877, 74.06368256], [108.07548412, 127.99022654]], [[ 66.12443902, 76.87897353], [114.70165583, 137.90124779]]])
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https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.nper.html