Join a sequence of arrays along an existing axis.
The arrays must have the same shape, except in the dimension corresponding to axis (the first, by default).
The axis along which the arrays will be joined. If axis is None, arrays are flattened before use. Default is 0.
If provided, the destination to place the result. The shape must be correct, matching that of what concatenate would have returned if no out argument were specified.
If provided, the destination array will have this dtype. Cannot be provided together with out.
New in version 1.20.0.
Controls what kind of data casting may occur. Defaults to ‘same_kind’. For a description of the options, please see casting.
New in version 1.20.0.
The concatenated array.
See also
ma.concatenateConcatenate function that preserves input masks.
array_splitSplit an array into multiple sub-arrays of equal or near-equal size.
splitSplit array into a list of multiple sub-arrays of equal size.
hsplitSplit array into multiple sub-arrays horizontally (column wise).
vsplitSplit array into multiple sub-arrays vertically (row wise).
dsplitSplit array into multiple sub-arrays along the 3rd axis (depth).
stackStack a sequence of arrays along a new axis.
blockAssemble arrays from blocks.
hstackStack arrays in sequence horizontally (column wise).
vstackStack arrays in sequence vertically (row wise).
dstackStack arrays in sequence depth wise (along third dimension).
column_stackStack 1-D arrays as columns into a 2-D array.
When one or more of the arrays to be concatenated is a MaskedArray, this function will return a MaskedArray object instead of an ndarray, but the input masks are not preserved. In cases where a MaskedArray is expected as input, use the ma.concatenate function from the masked array module instead.
>>> import numpy as np
>>> a = np.array([[1, 2], [3, 4]])
>>> b = np.array([[5, 6]])
>>> np.concatenate((a, b), axis=0)
array([[1, 2],
[3, 4],
[5, 6]])
>>> np.concatenate((a, b.T), axis=1)
array([[1, 2, 5],
[3, 4, 6]])
>>> np.concatenate((a, b), axis=None)
array([1, 2, 3, 4, 5, 6])
This function will not preserve masking of MaskedArray inputs.
>>> a = np.ma.arange(3)
>>> a[1] = np.ma.masked
>>> b = np.arange(2, 5)
>>> a
masked_array(data=[0, --, 2],
mask=[False, True, False],
fill_value=999999)
>>> b
array([2, 3, 4])
>>> np.concatenate([a, b])
masked_array(data=[0, 1, 2, 2, 3, 4],
mask=False,
fill_value=999999)
>>> np.ma.concatenate([a, b])
masked_array(data=[0, --, 2, 2, 3, 4],
mask=[False, True, False, False, False, False],
fill_value=999999)
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https://numpy.org/doc/2.4/reference/generated/numpy.concatenate.html