Compute the inverse of a matrix.
Given a square matrix a, return the matrix ainv satisfying a @ ainv = ainv @ a = eye(a.shape[0]).
Matrix to be inverted.
Inverse of the matrix a.
If a is not square or inversion fails.
See also
scipy.linalg.invSimilar function in SciPy.
numpy.linalg.condCompute the condition number of a matrix.
numpy.linalg.svdCompute the singular value decomposition of a matrix.
Broadcasting rules apply, see the numpy.linalg documentation for details.
If a is detected to be singular, a LinAlgError is raised. If a is ill-conditioned, a LinAlgError may or may not be raised, and results may be inaccurate due to floating-point errors.
Wikipedia, “Condition number”, https://en.wikipedia.org/wiki/Condition_number
>>> import numpy as np >>> from numpy.linalg import inv >>> a = np.array([[1., 2.], [3., 4.]]) >>> ainv = inv(a) >>> np.allclose(a @ ainv, np.eye(2)) True >>> np.allclose(ainv @ a, np.eye(2)) True
If a is a matrix object, then the return value is a matrix as well:
>>> ainv = inv(np.matrix(a))
>>> ainv
matrix([[-2. , 1. ],
[ 1.5, -0.5]])
Inverses of several matrices can be computed at once:
>>> a = np.array([[[1., 2.], [3., 4.]], [[1, 3], [3, 5]]])
>>> inv(a)
array([[[-2. , 1. ],
[ 1.5 , -0.5 ]],
[[-1.25, 0.75],
[ 0.75, -0.25]]])
If a matrix is close to singular, the computed inverse may not satisfy a @ ainv = ainv @ a = eye(a.shape[0]) even if a LinAlgError is not raised:
>>> a = np.array([[2,4,6],[2,0,2],[6,8,14]])
>>> inv(a) # No errors raised
array([[-1.12589991e+15, -5.62949953e+14, 5.62949953e+14],
[-1.12589991e+15, -5.62949953e+14, 5.62949953e+14],
[ 1.12589991e+15, 5.62949953e+14, -5.62949953e+14]])
>>> a @ inv(a)
array([[ 0. , -0.5 , 0. ], # may vary
[-0.5 , 0.625, 0.25 ],
[ 0. , 0. , 1. ]])
To detect ill-conditioned matrices, you can use numpy.linalg.cond to compute its condition number [1]. The larger the condition number, the more ill-conditioned the matrix is. As a rule of thumb, if the condition number cond(a) = 10**k, then you may lose up to k digits of accuracy on top of what would be lost to the numerical method due to loss of precision from arithmetic methods.
>>> from numpy.linalg import cond >>> cond(a) np.float64(8.659885634118668e+17) # may vary
It is also possible to detect ill-conditioning by inspecting the matrix’s singular values directly. The ratio between the largest and the smallest singular value is the condition number:
>>> from numpy.linalg import svd >>> sigma = svd(a, compute_uv=False) # Do not compute singular vectors >>> sigma.max()/sigma.min() 8.659885634118668e+17 # may vary
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