Expanding.sum(self, *args, **kwargs)
[source]
Calculate expanding sum of given DataFrame or Series.
Parameters: |
|
---|---|
Returns: |
|
See also
Series.sum
DataFrame.sum
>>> s = pd.Series([1, 2, 3, 4, 5]) >>> s 0 1 1 2 2 3 3 4 4 5 dtype: int64
>>> s.rolling(3).sum() 0 NaN 1 NaN 2 6.0 3 9.0 4 12.0 dtype: float64
>>> s.expanding(3).sum() 0 NaN 1 NaN 2 6.0 3 10.0 4 15.0 dtype: float64
>>> s.rolling(3, center=True).sum() 0 NaN 1 6.0 2 9.0 3 12.0 4 NaN dtype: float64
For DataFrame, each expanding sum is computed column-wise.
>>> df = pd.DataFrame({"A": s, "B": s ** 2}) >>> df A B 0 1 1 1 2 4 2 3 9 3 4 16 4 5 25
>>> df.rolling(3).sum() A B 0 NaN NaN 1 NaN NaN 2 6.0 14.0 3 9.0 29.0 4 12.0 50.0
© 2008–2012, AQR Capital Management, LLC, Lambda Foundry, Inc. and PyData Development Team
Licensed under the 3-clause BSD License.
https://pandas.pydata.org/pandas-docs/version/0.25.0/reference/api/pandas.core.window.Expanding.sum.html