DataFrame.to_dict(self, orient='dict', into=<class 'dict'>)
[source]
Convert the DataFrame to a dictionary.
The type of the key-value pairs can be customized with the parameters (see below).
Parameters: |
|
---|---|
Returns: |
|
See also
DataFrame.from_dict
DataFrame.to_json
>>> df = pd.DataFrame({'col1': [1, 2], ... 'col2': [0.5, 0.75]}, ... index=['row1', 'row2']) >>> df col1 col2 row1 1 0.50 row2 2 0.75 >>> df.to_dict() {'col1': {'row1': 1, 'row2': 2}, 'col2': {'row1': 0.5, 'row2': 0.75}}
You can specify the return orientation.
>>> df.to_dict('series') {'col1': row1 1 row2 2 Name: col1, dtype: int64, 'col2': row1 0.50 row2 0.75 Name: col2, dtype: float64}
>>> df.to_dict('split') {'index': ['row1', 'row2'], 'columns': ['col1', 'col2'], 'data': [[1, 0.5], [2, 0.75]]}
>>> df.to_dict('records') [{'col1': 1, 'col2': 0.5}, {'col1': 2, 'col2': 0.75}]
>>> df.to_dict('index') {'row1': {'col1': 1, 'col2': 0.5}, 'row2': {'col1': 2, 'col2': 0.75}}
You can also specify the mapping type.
>>> from collections import OrderedDict, defaultdict >>> df.to_dict(into=OrderedDict) OrderedDict([('col1', OrderedDict([('row1', 1), ('row2', 2)])), ('col2', OrderedDict([('row1', 0.5), ('row2', 0.75)]))])
If you want a defaultdict
, you need to initialize it:
>>> dd = defaultdict(list) >>> df.to_dict('records', into=dd) [defaultdict(<class 'list'>, {'col1': 1, 'col2': 0.5}), defaultdict(<class 'list'>, {'col1': 2, 'col2': 0.75})]
© 2008–2012, AQR Capital Management, LLC, Lambda Foundry, Inc. and PyData Development Team
Licensed under the 3-clause BSD License.
https://pandas.pydata.org/pandas-docs/version/0.25.0/reference/api/pandas.DataFrame.to_dict.html