MultiIndex.get_loc_level(self, key, level=0, drop_level=True)
[source]
Get both the location for the requested label(s) and the resulting sliced index.
Parameters: |
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Returns: |
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See also
MultiIndex.get_loc
MultiIndex.get_locs
>>> mi = pd.MultiIndex.from_arrays([list('abb'), list('def')], ... names=['A', 'B'])
>>> mi.get_loc_level('b') (slice(1, 3, None), Index(['e', 'f'], dtype='object', name='B'))
>>> mi.get_loc_level('e', level='B') (array([False, True, False], dtype=bool), Index(['b'], dtype='object', name='A'))
>>> mi.get_loc_level(['b', 'e']) (1, None)
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https://pandas.pydata.org/pandas-docs/version/0.25.0/reference/api/pandas.MultiIndex.get_loc_level.html