pandas.MultiIndex.set_levels

MultiIndex.set_levels(self, levels, level=None, inplace=False, verify_integrity=True) [source]

Set new levels on MultiIndex. Defaults to returning new index.

Parameters:	levels : sequence or list of sequence new level(s) to apply level : int, level name, or sequence of int/level names (default None) level(s) to set (None for all levels) inplace : bool if True, mutates in place verify_integrity : bool (default True) if True, checks that levels and codes are compatible
Returns:	new index (of same type and class…etc)

Examples

>>> idx = pd.MultiIndex.from_tuples([(1, 'one'), (1, 'two'),
                                    (2, 'one'), (2, 'two')],
                                    names=['foo', 'bar'])
>>> idx.set_levels([['a', 'b'], [1, 2]])
MultiIndex([('a', 1),
            ('a', 2),
            ('b', 1),
            ('b', 2)],
           names=['foo', 'bar'])
>>> idx.set_levels(['a', 'b'], level=0)
MultiIndex([('a', 'one'),
            ('a', 'two'),
            ('b', 'one'),
            ('b', 'two')],
           names=['foo', 'bar'])
>>> idx.set_levels(['a', 'b'], level='bar')
MultiIndex([(1, 'a'),
            (1, 'b'),
            (2, 'a'),
            (2, 'b')],
           names=['foo', 'bar'])
>>> idx.set_levels([['a', 'b'], [1, 2]], level=[0, 1])
MultiIndex([('a', 1),
            ('a', 2),
            ('b', 1),
            ('b', 2)],
           names=['foo', 'bar'])