Series.str.replace(self, pat, repl, n=-1, case=None, flags=0, regex=True) [source]
Replace occurrences of pattern/regex in the Series/Index with some other string. Equivalent to str.replace() or re.sub().
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When pat is a compiled regex, all flags should be included in the compiled regex. Use of case, flags, or regex=False with a compiled regex will raise an error.
When pat is a string and regex is True (the default), the given pat is compiled as a regex. When repl is a string, it replaces matching regex patterns as with re.sub(). NaN value(s) in the Series are left as is:
>>> pd.Series(['foo', 'fuz', np.nan]).str.replace('f.', 'ba', regex=True)
0 bao
1 baz
2 NaN
dtype: object
When pat is a string and regex is False, every pat is replaced with repl as with str.replace():
>>> pd.Series(['f.o', 'fuz', np.nan]).str.replace('f.', 'ba', regex=False)
0 bao
1 fuz
2 NaN
dtype: object
When repl is a callable, it is called on every pat using re.sub(). The callable should expect one positional argument (a regex object) and return a string.
To get the idea:
>>> pd.Series(['foo', 'fuz', np.nan]).str.replace('f', repr)
0 <_sre.SRE_Match object; span=(0, 1), match='f'>oo
1 <_sre.SRE_Match object; span=(0, 1), match='f'>uz
2 NaN
dtype: object
Reverse every lowercase alphabetic word:
>>> repl = lambda m: m.group(0)[::-1] >>> pd.Series(['foo 123', 'bar baz', np.nan]).str.replace(r'[a-z]+', repl) 0 oof 123 1 rab zab 2 NaN dtype: object
Using regex groups (extract second group and swap case):
>>> pat = r"(?P<one>\w+) (?P<two>\w+) (?P<three>\w+)"
>>> repl = lambda m: m.group('two').swapcase()
>>> pd.Series(['One Two Three', 'Foo Bar Baz']).str.replace(pat, repl)
0 tWO
1 bAR
dtype: object
Using a compiled regex with flags
>>> import re >>> regex_pat = re.compile(r'FUZ', flags=re.IGNORECASE) >>> pd.Series(['foo', 'fuz', np.nan]).str.replace(regex_pat, 'bar') 0 foo 1 bar 2 NaN dtype: object
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https://pandas.pydata.org/pandas-docs/version/0.25.0/reference/api/pandas.Series.str.replace.html