pandas.Index.equals

Index.equals(other)[source]

Determine if two Index object are equal.

The things that are being compared are:

• The elements inside the Index object.

• The order of the elements inside the Index object.

Parameters:

other:Any

The other object to compare against.

Returns:

bool

True if “other” is an Index and it has the same elements and order as the calling index; False otherwise.

Examples

>>> idx1 = pd.Index([1, 2, 3])
>>> idx1
Index([1, 2, 3], dtype='int64')
>>> idx1.equals(pd.Index([1, 2, 3]))
True

The elements inside are compared

>>> idx2 = pd.Index(["1", "2", "3"])
>>> idx2
Index(['1', '2', '3'], dtype='object')

>>> idx1.equals(idx2)
False

The order is compared

>>> ascending_idx = pd.Index([1, 2, 3])
>>> ascending_idx
Index([1, 2, 3], dtype='int64')
>>> descending_idx = pd.Index([3, 2, 1])
>>> descending_idx
Index([3, 2, 1], dtype='int64')
>>> ascending_idx.equals(descending_idx)
False

The dtype is not compared

>>> int64_idx = pd.Index([1, 2, 3], dtype='int64')
>>> int64_idx
Index([1, 2, 3], dtype='int64')
>>> uint64_idx = pd.Index([1, 2, 3], dtype='uint64')
>>> uint64_idx
Index([1, 2, 3], dtype='uint64')
>>> int64_idx.equals(uint64_idx)
True