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Computes the sum of elements across dimensions of a tensor.
tf.math.reduce_sum( input_tensor, axis=None, keepdims=False, name=None )
Reduces input_tensor
along the dimensions given in axis
. Unless keepdims
is true, the rank of the tensor is reduced by 1 for each entry in axis
. If keepdims
is true, the reduced dimensions are retained with length 1.
If axis
is None, all dimensions are reduced, and a tensor with a single element is returned.
# x has a shape of (2, 3) (two rows and three columns): x = tf.constant([[1, 1, 1], [1, 1, 1]]) x.numpy() array([[1, 1, 1], [1, 1, 1]], dtype=int32) # sum all the elements # 1 + 1 + 1 + 1 + 1+ 1 = 6 tf.reduce_sum(x).numpy() 6 # reduce along the first dimension # the result is [1, 1, 1] + [1, 1, 1] = [2, 2, 2] tf.reduce_sum(x, 0).numpy() array([2, 2, 2], dtype=int32) # reduce along the second dimension # the result is [1, 1] + [1, 1] + [1, 1] = [3, 3] tf.reduce_sum(x, 1).numpy() array([3, 3], dtype=int32) # keep the original dimensions tf.reduce_sum(x, 1, keepdims=True).numpy() array([[3], [3]], dtype=int32) # reduce along both dimensions # the result is 1 + 1 + 1 + 1 + 1 + 1 = 6 # or, equivalently, reduce along rows, then reduce the resultant array # [1, 1, 1] + [1, 1, 1] = [2, 2, 2] # 2 + 2 + 2 = 6 tf.reduce_sum(x, [0, 1]).numpy() 6
Args | |
---|---|
input_tensor | The tensor to reduce. Should have numeric type. |
axis | The dimensions to reduce. If None (the default), reduces all dimensions. Must be in the range [-rank(input_tensor), rank(input_tensor)] . |
keepdims | If true, retains reduced dimensions with length 1. |
name | A name for the operation (optional). |
Returns | |
---|---|
The reduced tensor, of the same dtype as the input_tensor. |
Equivalent to np.sum apart the fact that numpy upcast uint8 and int32 to int64 while tensorflow returns the same dtype as the input.
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Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/versions/r2.3/api_docs/python/tf/math/reduce_sum