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Computes the sum along segments of a tensor divided by the sqrt(N).

tf.math.unsorted_segment_sqrt_n( data, segment_ids, num_segments, name=None )

Read the section on segmentation for an explanation of segments.

This operator is similar to the `tf.math.unsorted_segment_sum`

operator. Additionally to computing the sum over segments, it divides the results by sqrt(N).

\(output_i = 1/sqrt(N_i) \sum_{j...} data[j...]\) where the sum is over tuples `j...`

such that `segment_ids[j...] == i`

with \N_i\ being the number of occurrences of id \i\.

If there is no entry for a given segment ID `i`

, it outputs 0.

Note that this op only supports floating point and complex dtypes, due to tf.sqrt only supporting these types.

If the given segment ID `i`

is negative, the value is dropped and will not be added to the sum of the segment.

Args | |
---|---|

`data` | A `Tensor` with floating point or complex dtype. |

`segment_ids` | An integer tensor whose shape is a prefix of `data.shape` . |

`num_segments` | An integer scalar `Tensor` . The number of distinct segment IDs. |

`name` | A name for the operation (optional). |

Returns | |
---|---|

A `Tensor` . Has same shape as data, except for the first `segment_ids.rank` dimensions, which are replaced with a single dimension which has size `num_segments` . |

© 2020 The TensorFlow Authors. All rights reserved.

Licensed under the Creative Commons Attribution License 3.0.

Code samples licensed under the Apache 2.0 License.

https://www.tensorflow.org/versions/r2.4/api_docs/python/tf/math/unsorted_segment_sqrt_n