Returns the min of x and y (i.e. x < y ? x : y) element-wise.
tf.raw_ops.Minimum( x, y, name=None )
Both inputs are number-type tensors (except complex). minimum
expects that both tensors have the same dtype
.
x = tf.constant([0., 0., 0., 0.]) y = tf.constant([-5., -2., 0., 3.]) tf.math.minimum(x, y) <tf.Tensor: shape=(4,), dtype=float32, numpy=array([-5., -2., 0., 0.], dtype=float32)>
Note that minimum
supports broadcast semantics.
x = tf.constant([-5., 0., 0., 0.]) y = tf.constant([-3.]) tf.math.minimum(x, y) <tf.Tensor: shape=(4,), dtype=float32, numpy=array([-5., -3., -3., -3.], dtype=float32)>
If inputs are not tensors, they will be converted to tensors. See tf.convert_to_tensor
.
x = tf.constant([-3.], dtype=tf.float32) tf.math.minimum([-5], x) <tf.Tensor: shape=(1,), dtype=float32, numpy=array([-5.], dtype=float32)>
Args | |
---|---|
x | A Tensor . Must be one of the following types: bfloat16 , half , float32 , float64 , uint8 , int16 , int32 , int64 . |
y | A Tensor . Must have the same type as x . |
name | A name for the operation (optional). |
Returns | |
---|---|
A Tensor . Has the same type as x . |
© 2020 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/versions/r2.4/api_docs/python/tf/raw_ops/Minimum