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Computes the sum along segments of a tensor divided by the sqrt(N).
tf.math.unsorted_segment_sqrt_n(
    data, segment_ids, num_segments, name=None
)
  Read the section on segmentation for an explanation of segments.
This operator is similar to the tf.math.unsorted_segment_sum operator. Additionally to computing the sum over segments, it divides the results by sqrt(N).
\(output_i = 1/sqrt(N_i) \sum_{j...} data[j...]\) where the sum is over tuples j... such that segment_ids[j...] == i with \N_i\ being the number of occurrences of id \i\.
If there is no entry for a given segment ID i, it outputs 0.
Note that this op only supports floating point and complex dtypes, due to tf.sqrt only supporting these types.
If the given segment ID i is negative, the value is dropped and will not be added to the sum of the segment.
| Args | |
|---|---|
| data | A Tensorwith floating point or complex dtype. | 
| segment_ids | An integer tensor whose shape is a prefix of data.shape. The values must be in the range[0, num_segments). The values are always validated to be in range on CPU, never validated on GPU. | 
| num_segments | An integer scalar Tensor. The number of distinct segment IDs. | 
| name | A name for the operation (optional). | 
| Returns | |
|---|---|
| A Tensor. Has same shape as data, except for the firstsegment_ids.rankdimensions, which are replaced with a single dimension which has sizenum_segments. | 
    © 2022 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 4.0.
Code samples licensed under the Apache 2.0 License.
    https://www.tensorflow.org/versions/r2.9/api_docs/python/tf/math/unsorted_segment_sqrt_n