tf.nn.l2_normalize(
x,
axis=None,
epsilon=1e-12,
name=None,
dim=None
)
Defined in tensorflow/python/ops/nn_impl.py.
See the guide: Neural Network > Normalization
Normalizes along dimension axis using an L2 norm. (deprecated arguments)
SOME ARGUMENTS ARE DEPRECATED. They will be removed in a future version. Instructions for updating: dim is deprecated, use axis instead
For a 1-D tensor with axis = 0, computes
output = x / sqrt(max(sum(x**2), epsilon))
For x with more dimensions, independently normalizes each 1-D slice along dimension axis.
x: A Tensor.axis: Dimension along which to normalize. A scalar or a vector of integers.epsilon: A lower bound value for the norm. Will use sqrt(epsilon) as the divisor if norm < sqrt(epsilon).name: A name for this operation (optional).dim: Deprecated alias for axis.A Tensor with the same shape as x.
© 2018 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/api_docs/python/tf/nn/l2_normalize