Constructs an unnamed object of specified type (which may be struct, union, or even array type) in-place.
( type ) { initializer-list } | (since C99) | |
( type ) { initializer-list , } | (since C99) | |
( type ) { } | (since C23) |
where.
| type | - | a type name specifying any complete object type or an array of unknown size, but not a VLA |
| initializer-list | - | list of initializers suitable for initialization of an object of type |
The compound literal expression constructs an unnamed object of the type specified by type and initializes it as specified by initializer-list. Designated initializers are accepted.
The type of the compound literal is type (except when type is an array of unknown size; its size is deduced from the initializer-list as in array initialization).
The value category of a compound literal is lvalue (its address can be taken).
The unnamed object to which the compound literal evaluates has static storage duration if the compound literal occurs at file scope and automatic storage duration if the compound literal occurs at block scope (in which case the object's lifetime ends at the end of the enclosing block).
Compound literals of const-qualified character or wide character array types may share storage with string literals.
(const char []){"abc"} == "abc" // might be 1 or 0, implementation-definedEach compound literal creates only a single object in its scope:
int f (void)
{
struct s {int i;} *p = 0, *q;
int j = 0;
again:
q = p, p = &((struct s){ j++ });
if (j < 2) goto again; // note; if a loop were used, it would end scope here,
// which would terminate the lifetime of the compound literal
// leaving p as a dangling pointer
return p == q && q->i == 1; // always returns 1
}Because compound literals are unnamed, a compound literal cannot reference itself (a named struct can include a pointer to itself).
Although the syntax of a compound literal is similar to a cast, the important distinction is that a cast is a non-lvalue expression while a compound literal is an lvalue.
#include <stdio.h>
int *p = (int[]){2, 4}; // creates an unnamed static array of type int[2]
// initializes the array to the values {2, 4}
// creates pointer p to point at the first element of
// the array
const float *pc = (const float []){1e0, 1e1, 1e2}; // read-only compound literal
struct point {double x,y;};
int main(void)
{
int n = 2, *p = &n;
p = (int [2]){*p}; // creates an unnamed automatic array of type int[2]
// initializes the first element to the value formerly
// held in *p
// initializes the second element to zero
// stores the address of the first element in p
void drawline1(struct point from, struct point to);
void drawline2(struct point *from, struct point *to);
drawline1(
(struct point){.x=1, .y=1}, // creates two structs with block scope and
(struct point){.x=3, .y=4}); // calls drawline1, passing them by value
drawline2(
&(struct point){.x=1, .y=1}, // creates two structs with block scope and
&(struct point){.x=3, .y=4}); // calls drawline2, passing their addresses
}
void drawline1(struct point from, struct point to)
{
printf("drawline1: `from` @ %p {%.2f, %.2f}, `to` @ %p {%.2f, %.2f}\n",
(void*)&from, from.x, from.y, (void*)&to, to.x, to.y);
}
void drawline2(struct point *from, struct point *to)
{
printf("drawline2: `from` @ %p {%.2f, %.2f}, `to` @ %p {%.2f, %.2f}\n",
(void*)from, from->x, from->y, (void*)to, to->x, to->y);
}Possible output:
drawline1: `from` @ 0x7ffd24facea0 {1.00, 1.00}, `to` @ 0x7ffd24face90 {3.00, 4.00}
drawline2: `from` @ 0x7ffd24facec0 {1.00, 1.00}, `to` @ 0x7ffd24faced0 {3.00, 4.00}
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