std::literals::chrono_literals::operator""h

constexpr std::chrono::hours operator ""h( unsigned long long hrs );

constexpr std::chrono::duration</*unspecified*/, std::ratio<3600,1>>
                             operator ""h( long double hrs );

Forms a std::chrono::duration literal representing hours.

Parameters

Return value

The std::chrono::duration literal.

Possible implementation

constexpr std::chrono::hours operator ""h(unsigned long long h)
{
    return std::chrono::hours(h);
}
constexpr std::chrono::duration<long double, ratio<3600,1>> operator ""h(long double h)
{
    return std::chrono::duration<long double, std::ratio<3600,1>>(h);
}

Notes

This operator is declared in the namespace std::literals::chrono_literals, where both literals and chrono_literals are inline namespaces. Access to this operator can be gained with:

• using namespace std::literals,
• using namespace std::chrono_literals, or
• using namespace std::literals::chrono_literals.

In addition, within the namespace std::chrono, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the classes in the chrono library, the corresponding literal operators become visible as well.

Example

#include <iostream>
#include <chrono>
 
int main()
{
    using namespace std::chrono_literals;
    auto day = 24h;
    auto halfhour = 0.5h;
    std::cout << "one day is " << day.count() << " hours\n"
              << "half an hour is " << halfhour.count() << " hours\n";
}

one day is 24 hours
half an hour is 0.5 hours

See also