std::set
Defined in header <set> | ||
---|---|---|
template< class InputIt, class Comp = std::less<typename std::iterator_traits<InputIt>::value_type>, class Alloc = std::allocator<typename std::iterator_traits<InputIt>::value_type>> set( InputIt, InputIt, Comp = Comp(), Alloc = Alloc() ) -> set<typename std::iterator_traits<InputIt>::value_type, Comp, Alloc>; | (1) | (since C++17) |
template< class Key, class Comp = std::less<Key>, class Alloc = std::allocator<Key> > set( std::initializer_list<Key>, Comp = Comp(), Alloc = Alloc() ) -> set<Key, Comp, Alloc>; | (2) | (since C++17) |
template< class InputIt, class Alloc > set( InputIt, InputIt, Alloc ) -> set<typename std::iterator_traits<InputIt>::value_type, std::less<typename std::iterator_traits<InputIt>::value_type>, Alloc>; | (3) | (since C++17) |
template< class Key, class Alloc > set( std::initializer_list<Key>, Alloc ) -> set<Key, std::less<Key>, Alloc>; | (4) | (since C++17) |
template< ranges::input_range R, class Compare = less<ranges::range_value_t<R>>, class Alloc = std::allocator<ranges::range_value_t<R>> > set( std::from_range_t, R&&, Compare = Compare(), Alloc = Alloc() ) -> set<ranges::range_value_t<R>, Compare, Alloc>; | (5) | (since C++23) |
template< ranges::input_range R, class Alloc > set( std::from_range_t, R&&, Alloc ) -> set<ranges::range_value_t<R>, std::less<ranges::range_value_t<R>>, Alloc>; | (6) | (since C++23) |
set
to allow deduction from an iterator range (overloads (1,3)) and std::initializer_list
(overloads (2,4)).set
to allow deduction from a std::from_range_t
tag and an input_range
.These overloads participate in overload resolution only if InputIt
satisfies LegacyInputIterator, Alloc
satisfies Allocator, and Comp
does not satisfy Allocator.
Note: the extent to which the library determines that a type does not satisfy LegacyInputIterator is unspecified, except that as a minimum integral types do not qualify as input iterators. Likewise, the extent to which it determines that a type does not satisfy Allocator is unspecified, except that as a minimum the member type Alloc::value_type
must exist and the expression std::declval<Alloc&>().allocate(std::size_t{})
must be well-formed when treated as an unevaluated operand.
Feature-test macro | Value | Std | Comment |
---|---|---|---|
__cpp_lib_containers_ranges | 202202L | (C++23) | Ranges-aware construction and insertion; overload (5,6) |
#include <set> int main() { // guide #2 deduces std::set<int> std::set s = {1,2,3,4}; // guide #1 deduces std::set<int> std::set s2(s.begin(), s.end()); }
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