The instanceof
operator tests to see if the prototype
property of a constructor appears anywhere in the prototype chain of an object. The return value is a boolean value. Its behavior can be customized with Symbol.hasInstance
.
The instanceof
operator tests to see if the prototype
property of a constructor appears anywhere in the prototype chain of an object. The return value is a boolean value. Its behavior can be customized with Symbol.hasInstance
.
object instanceof constructor
object
The object to test.
constructor
Constructor to test against.
TypeError
Thrown if constructor
is not an object. If constructor
doesn't have a @@hasInstance
method, it must also be a function.
The instanceof
operator tests the presence of constructor.prototype
in object
's prototype chain. This usually (though not always) means object
was constructed with constructor
.
// defining constructors function C() {} function D() {} const o = new C(); // true, because: Object.getPrototypeOf(o) === C.prototype o instanceof C; // false, because D.prototype is nowhere in o's prototype chain o instanceof D; o instanceof Object; // true, because: C.prototype instanceof Object; // true // Re-assign `constructor.prototype`: you should // rarely do this in practice. C.prototype = {}; const o2 = new C(); o2 instanceof C; // true // false, because C.prototype is nowhere in // o's prototype chain anymore o instanceof C; D.prototype = new C(); // add C to [[Prototype]] linkage of D const o3 = new D(); o3 instanceof D; // true o3 instanceof C; // true since C.prototype is now in o3's prototype chain
Note that the value of an instanceof
test can change if constructor.prototype
is re-assigned after creating the object (which is usually discouraged). It can also be changed by changing object
's prototype using Object.setPrototypeOf
.
Classes behave in the same way, because classes also have the prototype
property.
class A {} class B extends A {} const o1 = new A(); // true, because Object.getPrototypeOf(o1) === A.prototype o1 instanceof A; // false, because B.prototype is nowhere in o1's prototype chain o1 instanceof B; const o2 = new B(); // true, because Object.getPrototypeOf(Object.getPrototypeOf(o2)) === A.prototype o2 instanceof A; // true, because Object.getPrototypeOf(o2) === B.prototype o2 instanceof B;
For bound functions, instanceof
looks up for the prototype
property on the target function, since bound functions don't have prototype
.
class Base {} const BoundBase = Base.bind(null, 1, 2); console.log(new Base() instanceof BoundBase); // true
If constructor
has a Symbol.hasInstance
method, the method will be called in priority, with object
as its only argument and constructor
as this
.
// This class allows plain objects to be disguised as this class's instance, // as long as the object has a particular flag as its property. class Forgeable { static isInstanceFlag = Symbol("isInstanceFlag"); static [Symbol.hasInstance](obj) { return Forgeable.isInstanceFlag in obj; } } const obj = { [Forgeable.isInstanceFlag]: true }; console.log(obj instanceof Forgeable); // true
Because all functions inherit from Function.prototype
by default, most of the time, the Function.prototype[@@hasInstance]
method specifies the behavior of instanceof
when the right-hand side is a function. See the Symbol.hasInstance
page for the exact algorithm of instanceof
.
JavaScript execution environments (windows, frames, etc.) are each in their own realm. This means that they have different built-ins (different global object, different constructors, etc.). This may result in unexpected results. For instance, [] instanceof window.frames[0].Array
will return false
, because Array.prototype !== window.frames[0].Array.prototype
and arrays in the current realm inherit from the former.
This may not make sense at first, but for scripts dealing with multiple frames or windows, and passing objects from one context to another via functions, this will be a valid and strong issue. For instance, you can securely check if a given object is in fact an Array using Array.isArray()
, neglecting which realm it comes from.
For example, to check if a Node
is an SVGElement
in a different context, you can use myNode instanceof myNode.ownerDocument.defaultView.SVGElement
.
The following example shows the behavior of instanceof
with String
objects.
const literalString = "This is a literal string"; const stringObject = new String("String created with constructor"); literalString instanceof String; // false, string primitive is not a String stringObject instanceof String; // true literalString instanceof Object; // false, string primitive is not an Object stringObject instanceof Object; // true stringObject instanceof Date; // false
The following example shows the behavior of instanceof
with Date
objects.
const myDate = new Date(); myDate instanceof Date; // true myDate instanceof Object; // true myDate instanceof String; // false
The following example shows the behavior of instanceof
with objects created using Object.create()
.
function Shape() {} function Rectangle() { Shape.call(this); // call super constructor. } Rectangle.prototype = Object.create(Shape.prototype); Rectangle.prototype.constructor = Rectangle; const rect = new Rectangle(); rect instanceof Object; // true rect instanceof Shape; // true rect instanceof Rectangle; // true rect instanceof String; // false const literalObject = {}; const nullObject = Object.create(null); nullObject.name = "My object"; literalObject instanceof Object; // true, every object literal has Object.prototype as prototype ({}) instanceof Object; // true, same case as above nullObject instanceof Object; // false, prototype is end of prototype chain (null)
The following code creates an object type Car
and an instance of that object type, mycar
. The instanceof
operator demonstrates that the mycar
object is of type Car
and of type Object
.
function Car(make, model, year) { this.make = make; this.model = model; this.year = year; } const mycar = new Car("Honda", "Accord", 1998); const a = mycar instanceof Car; // returns true const b = mycar instanceof Object; // returns true
To test if an object is not an instanceof
a specific constructor, you can do:
if (!(mycar instanceof Car)) { // Do something, like: // mycar = new Car(mycar) }
This is really different from:
if (!mycar instanceof Car) { // unreachable code }
This will always be false
. (!mycar
will be evaluated before instanceof
, so you always try to know if a boolean is an instance of Car
).
A common pitfall of using instanceof
is believing that, if x instanceof C
, then x
was created using C
as constructor. This is not true, because x
could be directly assigned with C.prototype
as its prototype. In this case, if your code reads private fields of C
from x
, it would still fail:
class C { #value = "foo"; static getValue(x) { return x.#value; } } const x = { __proto__: C.prototype }; if (x instanceof C) { console.log(C.getValue(x)); // TypeError: Cannot read private member #value from an object whose class did not declare it }
To avoid this, you can override the behavior of instanceof
by adding a Symbol.hasInstance
method to C
, so that it does a branded check with in
:
class C { #value = "foo"; static [Symbol.hasInstance](x) { return #value in x; } static getValue(x) { return x.#value; } } const x = { __proto__: C.prototype }; if (x instanceof C) { // Doesn't run, because x is not a C console.log(C.getValue(x)); }
Note that you may want to limit this behavior to the current class; otherwise, it could lead to false positives for subclasses:
class D extends C {} console.log(new C() instanceof D); // true; because D inherits @@hasInstance from C
You could do this by checking that this
is the current constructor:
class C { #value = "foo"; static [Symbol.hasInstance](x) { return this === C && #value in x; } } class D extends C {} console.log(new C() instanceof D); // false console.log(new C() instanceof C); // true console.log({ __proto__: C.prototype } instanceof C); // false
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https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/instanceof