numpy.polynomial.chebyshev.chebdiv(c1, c2)
[source]
Divide one Chebyshev series by another.
Returns the quotient-with-remainder of two Chebyshev series c1
/ c2
. The arguments are sequences of coefficients from lowest order “term” to highest, e.g., [1,2,3] represents the series T_0 + 2*T_1 + 3*T_2
.
Parameters: |
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Returns: |
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In general, the (polynomial) division of one C-series by another results in quotient and remainder terms that are not in the Chebyshev polynomial basis set. Thus, to express these results as C-series, it is typically necessary to “reproject” the results onto said basis set, which typically produces “unintuitive” (but correct) results; see Examples section below.
>>> from numpy.polynomial import chebyshev as C >>> c1 = (1,2,3) >>> c2 = (3,2,1) >>> C.chebdiv(c1,c2) # quotient "intuitive," remainder not (array([3.]), array([-8., -4.])) >>> c2 = (0,1,2,3) >>> C.chebdiv(c2,c1) # neither "intuitive" (array([0., 2.]), array([-2., -4.]))
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https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.polynomial.chebyshev.chebdiv.html