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/TensorFlow 1.15

tf.enable_v2_tensorshape

In TensorFlow 2.0, iterating over a TensorShape instance returns values.

This enables the new behavior.

Concretely, tensor_shape[i] returned a Dimension instance in V1, but it V2 it returns either an integer, or None.

Examples:

#######################
# If you had this in V1:
value = tensor_shape[i].value

# Do this in V2 instead:
value = tensor_shape[i]

#######################
# If you had this in V1:
for dim in tensor_shape:
  value = dim.value
  print(value)

# Do this in V2 instead:
for value in tensor_shape:
  print(value)

#######################
# If you had this in V1:
dim = tensor_shape[i]
dim.assert_is_compatible_with(other_shape)  # or using any other shape method

# Do this in V2 instead:
if tensor_shape.rank is None:
  dim = Dimension(None)
else:
  dim = tensor_shape.dims[i]
dim.assert_is_compatible_with(other_shape)  # or using any other shape method

# The V2 suggestion above is more explicit, which will save you from
# the following trap (present in V1):
# you might do in-place modifications to `dim` and expect them to be reflected
# in `tensor_shape[i]`, but they would not be.

© 2020 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/versions/r1.15/api_docs/python/tf/enable_v2_tensorshape