|View source on GitHub|
Normalizes along dimension
axis using an L2 norm.
tf.math.l2_normalize( x, axis=None, epsilon=1e-12, name=None )
For a 1-D tensor with
axis = 0, computes
output = x / sqrt(max(sum(x**2), epsilon))
x with more dimensions, independently normalizes each 1-D slice along dimension
| || A |
| ||Dimension along which to normalize. A scalar or a vector of integers.|
| || A lower bound value for the norm. Will use |
| ||A name for this operation (optional).|
| A |
© 2020 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.