For variables, specifies that the type of the variable that is being declared will be automatically deduced from its initializer.
For functions, specifies that the return type will be deduced from its return statements. | (since C++14) |
For non-type template parameters, specifies that the type will be deduced from the argument. | (since C++17) |
type-constraint (optional) auto | (1) | (since C++11) |
type-constraint (optional) decltype ( auto ) | (2) | (since C++14) |
type-constraint | - | (since C++20) a concept name, optionally qualified, optionally followed by a template argument list enclosed in <> |
The placeholder auto
may be accompanied by modifiers, such as const
or &
, which will participate in the type deduction. The placeholder decltype(auto)
must be the sole constituent of the declared type. (since C++14).
A placeholder type specifier may appear in the following contexts:
auto x = expr;
as a type specifier. The type is deduced from the initializer. auto
or type-constraint auto
(since C++20), the variable type is deduced from the initializer using the rules for template argument deduction from a function call (see template argument deduction — other contexts for details). const auto& i = expr;
, the type of i
is exactly the type of the argument u
in an imaginary template template<class U> void f(const U& u)
if the function call f(expr)
was compiled. Therefore, auto&&
may be deduced either as an lvalue reference or rvalue reference according to the initializer, which is used in range-based for loop. If the placeholder type specifier is | (since C++14) |
If the placeholder type specifier is used to declare multiple variables, the deduced types must match. For example, the declaration auto i = 0, d = 0.0;
is ill-formed, while the declaration auto i = 0, *p = &i;
is well-formed and the auto
is deduced as int
.
new T init
(where T
contains a placeholder type, init is either a parenthesized initializer or a brace-enclosed initializer list), the type of T
is deduced as if for variable x
in the invented declaration T x init;
. auto& f();
. The return type is deduced from the operand of its non-discarded (since C++17) return statement. template<auto I> struct A;
. Its type is deduced from the corresponding argument. The | (since C++23) |
Furthermore,
| (since C++14) |
Type constraintIf type-constraint is present, let
Deduction fails if the constraint expression is invalid or returns | (since C++20) |
Until C++11, auto
had the semantic of a storage duration specifier.
Mixing auto
variables and functions in one declaration, as in auto f() -> int, i = 0;
is not allowed.
The auto
specifier may also be used with a function declarator that is followed by a trailing return type, in which case the declared return type is that trailing return type (which may again be a placeholder type).
auto (*p)() -> int; // declares p as pointer to function returning int auto (*q)() -> auto = p; // declares q as pointer to function returning T // where T is deduced from the type of p
The | (since C++17) |
The | (concepts TS) |
Feature-test macro | Value | Std | Comment |
---|---|---|---|
__cpp_decltype_auto | 201304L | (C++14) |
decltype(auto) |
#include <iostream> #include <utility> template<class T, class U> auto add(T t, U u) { return t + u; } // the return type is the type of operator+(T, U) // perfect forwarding of a function call must use decltype(auto) // in case the function it calls returns by reference template<class F, class... Args> decltype(auto) PerfectForward(F fun, Args&&... args) { return fun(std::forward<Args>(args)...); } template<auto n> // C++17 auto parameter declaration auto f() -> std::pair<decltype(n), decltype(n)> // auto can't deduce from brace-init-list { return {n, n}; } int main() { auto a = 1 + 2; // type of a is int auto b = add(1, 1.2); // type of b is double static_assert(std::is_same_v<decltype(a), int>); static_assert(std::is_same_v<decltype(b), double>); auto c0 = a; // type of c0 is int, holding a copy of a decltype(auto) c1 = a; // type of c1 is int, holding a copy of a decltype(auto) c2 = (a); // type of c2 is int&, an alias of a std::cout << "before modification through c2, a = " << a << '\n'; ++c2; std::cout << " after modification through c2, a = " << a << '\n'; auto [v, w] = f<0>(); //structured binding declaration auto d = {1, 2}; // OK: type of d is std::initializer_list<int> auto n = {5}; // OK: type of n is std::initializer_list<int> // auto e{1, 2}; // Error as of DR n3922, std::initializer_list<int> before auto m{5}; // OK: type of m is int as of DR n3922, initializer_list<int> before // decltype(auto) z = { 1, 2 } // Error: {1, 2} is not an expression // auto is commonly used for unnamed types such as the types of lambda expressions auto lambda = [](int x) { return x + 3; }; // auto int x; // valid C++98, error as of C++11 // auto x; // valid C, error in C++ [](...){}(c0, c1, v, w, d, n, m, lambda); // suppresses "unused variable" warnings }
Possible output:
before modification through c2, a = 3 after modification through c2, a = 4
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
CWG 1265 | C++11 | the auto specifier could be used to declare a function with a trailingreturn type and define a variable in one declaration statement | prohibited |
CWG 1346 | C++11 | a parenthesized expression list could not be assigned to an auto variable | allowed |
CWG 1347 | C++11 | a declaration with the auto specifier could define two variableswith types T and std::initializer_list<T> respectively | prohibited |
CWG 1852 | C++14 | the auto specifier in decltype(auto) was also a placeholder | not a placeholder in this case |
© cppreference.com
Licensed under the Creative Commons Attribution-ShareAlike Unported License v3.0.
https://en.cppreference.com/w/cpp/language/auto