constexpr V base() const& requires std::copy_constructible<V>; | (1) | (since C++20) |
constexpr V base() &&; | (2) | (since C++20) |
Returns a copy of the underlying view.
(none).
A copy of the underlying view.
#include <iostream> #include <ranges> #include <string_view> void print(std::string_view rem, auto const& r, std::string_view post = "\n") { for (std::cout << rem; auto const& e : r) std::cout << e; std::cout << post; } int main() { constexpr std::string_view keywords{ "this,..throw,..true,..try,.." }; constexpr std::string_view pattern{",.."}; constexpr std::ranges::lazy_split_view lazy_split_view{keywords, pattern}; print("base() = [", lazy_split_view.base(), "]\n" "substrings: "); for (auto const& split: lazy_split_view) print("[", split, "] "); }
Output:
base() = [this,..throw,..true,..try,..] substrings: [this] [throw] [true] [try] []
(C++20) | returns a copy of the underlying (adapted) view (public member function of std::ranges::split_view<V,Pattern> ) |
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