std::function
Defined in header <functional> | ||
---|---|---|
template< class R, class... ArgTypes > function( R(*)(ArgTypes...) ) -> function<R(ArgTypes...)>; | (1) | (since C++17) |
template< class F > function( F ) -> function</*see below*/>; | (2) | (since C++17) |
template< class F > function( F ) -> function</*see below*/>; | (3) | (since C++23) |
template< class F > function( F ) -> function</*see below*/>; | (4) | (since C++23) |
&F::operator()
is well-formed when treated as an unevaluated operand and decltype(&F::operator())
is of the form R(G::*)(A...)
(optionally cv-qualified, optionally noexcept, optionally lvalue reference qualified). The deduced type is std::function<R(A...)>
.&F::operator()
is well-formed when treated as an unevaluated operand and F::operator()
is an explicit object parameter function whose type is of form R(G, A...)
or R(G, A...) noexcept
. The deduced type is std::function<R(A...)>
.&F::operator()
is well-formed when treated as an unevaluated operand and F::operator()
is a static member function whose type is of form R(A...)
or R(A...) noexcept
. The deduced type is std::function<R(A...)>
.These deduction guides do not allow deduction from a function with ellipsis parameter, and the ...
in the types is always treated as a pack expansion.
The type deduced by these deduction guides may change in a later standard revision (in particular, this might happen if noexcept
support is added to std::function
in a later standard).
#include <functional> int func(double) { return 0; } int main() { std::function f{func}; // guide #1 deduces function<int(double)> int i = 5; std::function g = [&](double) { return i; }; // guide #2 deduces function<int(double)> }
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR | Applied to | Behavior as published | Correct behavior |
---|---|---|---|
LWG 3238 | C++17 | behavior of (2) was unclear whenF::operator() is &&-qualified | clarified to be excluded from overload resolution |
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